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Mind Blogging SQL Challenges



  1. Query an alphabetically ordered list of all names in OCCUPATIONS, immediately followed by the first letter of each profession as a parenthetical (i.e.: enclosed in parentheses). For example: AnActorName(A)ADoctorName(D)AProfessorName(P), and ASingerName(S).
  2. Query the number of ocurrences of each occupation in OCCUPATIONS. Sort the occurrences in ascending order, and output them in the following format: 
    There are total [occupation_count] [occupation]s.
    
    where [occupation_count] is the number of occurrences of an occupation in OCCUPATIONS and [occupation] is the lowercase occupation name. If more than one Occupation has the same [occupation_count], they should be ordered alphabetically.
Note: There will be at least two entries in the table for each type of occupation.
Input Format
The OCCUPATIONS table is described as follows:Occupation will only contain one of the following values: DoctorProfessorSinger or Actor.
Sample Input
An OCCUPATIONS table that contains the following records:
Sample Output
Ashely(P)
Christeen(P)
Jane(A)
Jenny(D)
Julia(A)
Ketty(P)
Maria(A)
Meera(S)
Priya(S)
Samantha(D)
There are total 2 doctors.
There are total 2 singers.
There are total 3 actors.
There are total 3 professors.

QUERY
select concat(name,"(",substring(occupation,1,1),")")from occupations order by name asc;
select concat("There are total ",count(occupation),' ',lower(occupation),'s.') from occupations group by occupation order by count(occupation) asc,occupation asc;

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